Answer
a. $20\ in$
b. $\frac{3}{8}\ Hz$
c. $\frac{8}{3}\ sec$
Work Step by Step
Based on the given equation $d=10sin(\frac{3\pi}{4}t)$, we have:
a. The amplitude is $|A|=10\ in$ and the maximum displacement (peak to peak) is $2|A|=2(10)=20\ in$
b. The frequency is $f=\frac{1}{p}=\frac{3\pi/4}{2\pi}=\frac{3}{8}\ Hz$ (cycles per second)
c. The time required for one oscillation is the period $p=\frac{1}{f}=\frac{8}{3}\ sec$
