Answer
The current when the resistance is $10$ ohms is $11$ Amperes.
Work Step by Step
We have to write the relation between $ I $ and $ R $ as,
$\begin{align}
& I\propto \frac{1}{R} \\
& I=\frac{k}{R}
\end{align}$
Where $ k $ is the constant of proportionality.
Put the value of $ R=22$ and $ I=5$ in the equation to get the value of $ k $ as:
$\begin{align}
& 5=\frac{k}{22} \\
& k=5\cdot 22 \\
& k=110
\end{align}$
So, the equation becomes $ I=\frac{110}{R}$.
Then, one has to find the value of $ I $ when $ R $ is $10$ as:
$\begin{align}
& I=\frac{110}{10} \\
& =11
\end{align}$
Thus, the current when resistance is $10$ ohms is $11$ Amperes.
