Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 282: 102

Answer

a. $140$ yards, $1200\ yard^2$ b. $140$ yards, $1000\ yard^2$

Work Step by Step

a. Given $l=40$ yards and $w=30$ yards, we have the perimeter $p=2(l+w)=2(40+30)=140$ yards, and the area $A=lw=40\times30=1200\ yard^2$ b. Given $l=50$ yards and $w=20$ yards, we have the perimeter $p=2(l+w)=2(50+20)=140$ yards, and the area $A=lw=50\times20=1000\ yard^2$
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