Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.3 - More on Functions and Their Graphs - Exercise Set - Page 197: 51

Answer

See the full explanation below.

Work Step by Step

(a) The input values to the function are known as the domain of the function. In the graph, usually x-values are the input values to the function, the graph of which is plotted. Hence, the domain of the function denotes the x-values of the graph. As the graph of $f$ extends to $-\infty $ in the negative x-direction and to $3$ in the positive x-direction, the domain of f is $\left( -\infty ,3 \right]$. Hence, the domain of $f$ is $\left( -\infty ,3 \right]$. (b) The values that are the output of the function are known as the range of the function. In the graph, usually y-values are the output values of the function, the graph of which is plotted. Hence,the range of the function is denoted by the y-values of the graph . As the graph of $f$ extends to $-\infty $ in the negative y-direction and to $4$ in the positive y-direction, the range of f is $\left( -\infty ,4 \right]$. Hence, the range of $f$ is $\left( -\infty ,4 \right]$. (c) The zeros of the function are the values of x for which the value of the function is zero. So, the zeros of $f$ are $-\text{3 and 3}$. Hence, the zeros of $f$ are $-\text{3 and 3}$. (d) The value of $f\left( 0 \right)$ is the value of function when $x=0$. So, the value is $f\left( 0 \right)=3$. Hence, the value $f\left( 0 \right)$ is $3$. (e) The function is said to be increasing when with the increase in x-values, there is a corresponding increase in y-values of the graph of the function. Thus, the value of the provided function increases in the interval $\left( -\infty ,1 \right)$. Hence, the interval in which $f$ is increasing is $\left( -\infty ,1 \right)$. (f) The function is said to be decreasing when with the increase in x-values, there is a decrease in y-values of the graph of the function. Thus, the value of the provided function decreases in the interval $\left( 1,3 \right)$. Hence, the interval in which $f$ is decreasing is $\left( 1,3 \right)$. (g) The given function has values less than or equal to zero, that is, the value of the provided function $f\left( x \right)\le 0$ is for the values of x that lies in the intervals $\left( -\infty \text{,}-\text{3} \right]$. Hence, the values of x for which $f\left( x \right)\le 0$ lies in the interval $\left( -\infty \text{,}-\text{3} \right]$. (h) The relative maximum of a function will be at that value of x at which y-value will be maximum as compared to all other points. Thus, the value of the provided function has maximum value at $x=1$ and the relative maxima is 4. Hence, the provided function has relative maxima at x=1 and the maxima is 4. (i) The value of the provided function has value 4 at $x=1$. Hence, the value of x for which $f\left( x \right)=4$ is 1. (j) As the value of y is approximately 2 when x is −1, the value of $f\left( -1 \right)$ is positive. Hence, the value of $f\left( -1 \right)$ is positive.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.