Answer
See below.
Work Step by Step
$LHS=ln(|1+cos\theta|)(|1-cos\theta|)=ln|1-cos^2\theta|=ln|sin^2\theta|=2ln|sin\theta|=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 99
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