Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 92

Answer

See below

Work Step by Step

$LHS=4a^2sin^2\theta cos^2\theta+a^2cos^4\theta-2a^2sin^2\theta cos^2\theta+a^2sin^4\theta=a^2cos^4\theta+2a^2sin^2\theta cos^2\theta+a^2sin^4\theta=a^2(cos^2\theta+sin^2\theta)^2=a^2=RHS$
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