Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.4 Trigonometric Identities - 7.4 Assess Your Understanding - Page 477: 89

Answer

See below.

Work Step by Step

Step 1. To prove the given identify, we need to show $sin\theta(1+sin\theta+cos\theta)=(1+cos\theta)(1+sin\theta-cos\theta)$ Step 2. $LHS=sin\theta+sin^2\theta+sin\theta cos\theta$ Step 3. $RHS=1+sin\theta-cos\theta+cos\theta+sin\theta cos\theta-cos^2\theta=sin\theta+sin\theta cos\theta+sin^2\theta=LHS$
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