Answer
Amplitude:$2$, period: $\frac{2}{3}$.
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin\omega x$.
Hence $A=|-2|=2$, $\omega=3\pi.$
To get the period we can use the formula: $T=\frac{2\pi}{\omega}=\frac{2\pi}{3\pi}=\frac{2}{3}.$
