Answer
$1$
Work Step by Step
I know that $\sec x=\frac{1}{\cos(x)}$, hence $\frac{1}{\sec^2{x}}=\cos^2{x}.$
We also know that $\sin^2{x}+\cos^2{x}=1$.
Hence: $\frac{1}{\sec^2{x}}+\sin^2{x}=\cos^2{x}+\sin^2{x}=1$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 11
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