Answer
$(0,1)U(1,\infty)$
Work Step by Step
Step 1. The domain requirement(s) for this function are $x\gt0$ and $ln\ x\ne0$
Step 2. For $ln\ x\ne0$, we have $x\ne 1$
Step 3. Thus we have the domain as $(0,1)U(1,\infty)$
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