Answer
$30$
Work Step by Step
We know that $P(n,r)=\dfrac{n!}{(n-r)!}.$
Hence,
$P(6,2)=\dfrac{6!}{(6-2)!}=\dfrac{6\cdot5\cdot4!}{4!}=6\cdot5=30.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 7
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