Answer
The ordered arrangements:
$ab,ac,ad,ae$
$ba,bc,bd,be$
$ca,cb,cd,ce$
$da,db,dc,de$
$ea,eb,ec,ed$
$P(5,2)=20$.
Work Step by Step
The ordered arrangements:
$ab,ac,ad,ae$
$ba,bc,bd,be$
$ca,cb,cd,ce$
$da,db,dc,de$
$ea,eb,ec,ed$
We know that $P(n,r)=n(n-1)(n-2)...(n-k+1).$ Also $P(n,0)=1$ by convention.
Hence $P(5,2)=5\cdot4=20$.