Answer
$$\frac{A^3}{3B^3}$$
Work Step by Step
Simplifying the given expression using the rules of radicals, we find:
$$3^{-1}A^{-1}B^{-1}A^4B^{-2} \\ \frac{1}{3}A^3B^{-3} \\ \frac{A^3}{3B^3}$$
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