Answer
$\pm r^2$
Work Step by Step
Use the fact that $\sqrt{a}=a^\frac{1}{2}$ along with the fact that $(a^b)^n=a^{bn}$ to get $$\sqrt{r^4}=r^{\frac{4}{2}}=r^2$$ However, $(-r^2)(-r^2)=r^4$ also. So, $\pm r^2$ is the result.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 4 - Exponential Functions - Exercises to Skills for Chapter 4 - Page 185: 42
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