Answer
$\pm r$
Work Step by Step
Use the fact that $\sqrt{a}=a^\frac{1}{2}$ to simplify the expression to $$\sqrt{r^2}=(r^2)^\frac{1}{2}=r^{2 \cdot \frac{1}{2}}=r$$ However, $(-r)(-r)=r^2$. $r$ and $-r$ must both be results.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 4 - Exponential Functions - Exercises to Skills for Chapter 4 - Page 185: 40
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