Answer
See below:
Work Step by Step
Consider the provided equation:
\[5x-3y=15\](1)
For \[x\text{-intercept}\], substitute \[y=0\] in equation (1).
That is,
\[\begin{align}
& 5x-3\left( 0 \right)=15 \\
& 5x=15 \\
& x=\frac{15}{5} \\
& x=3
\end{align}\]
Therefore, the line passes through \[\left( 3,0 \right)\].
and
For\[y\text{-intercept}\], substitute \[x=0\] in equation (1).
That is,
\[\begin{align}
& 5\left( 0 \right)-3y=15 \\
& -3y=15 \\
& y=-\frac{15}{5} \\
& =-5
\end{align}\]
Therefore, the line passes through \[\left( 0,-5 \right)\].
Now, plot the points \[\left( 3,0 \right)\]and \[\left( 0,-5 \right)\],then join the line.
The resulting graph is shown below:
