Answer
See below:
Work Step by Step
Consider the provided equation:
\[2x-3y=6\]….(1)
For\[x\text{-intercept}\], substitute \[y=0\] in equation (1).
That is.,
\[\begin{align}
& 2x-3\left( 0 \right)=6 \\
& 2x= \\
& x=\frac{6}{2} \\
& x=3
\end{align}\]
Therefore, the line passes through,\[\left( 3,0 \right)\].
And,
For\[y\text{-intercept}\], substitute \[x=0\] in equation (1).
That is.,
\[\begin{align}
& 2\left( 0 \right)-3y=6 \\
& -3y=6 \\
& y=-\frac{6}{3} \\
& =-2
\end{align}\]
Therefore, the line passes through,\[\left( 0,-2 \right)\].
Now, plot the points \[\left( 3,0 \right)\]and \[\left( 0,-2 \right)\]then join the line.
The resulting graph is shown above.
