Answer
$\dfrac{7^4}{7^6} = 7^{-2}=\dfrac{1}{49}$
Work Step by Step
RECALL:
For any non-zero real number $a$,
$\dfrac{a^m}{a^n} = a^{m-n}$
Use the rule above to find:
$\\=7^{4-6}
\\=7^{-2}$
RECALL:
$a^{-m} = \dfrac{1}{a^m}$
where $a$ is a non-zero real number
Use this rule to find:
$7^{-2}=\dfrac{1}{7^2} =\dfrac{1}{49}$
