Answer
shown below
Work Step by Step
(a)
For the population growth to be geometric, the ratio of adjacent term must be constant so,
\[\begin{align}
& r=\frac{21.27}{20.85} \\
& =1.02 \\
& =\frac{21.70}{21.27} \\
& =1.02
\end{align}\]
And,
\[\begin{align}
& r=\frac{22.13}{21.70} \\
& =1.02 \\
& =\frac{22.57}{22.13} \\
& =1.02
\end{align}\]
And,
\[\begin{align}
& r=\frac{23.02}{22.57} \\
& =1.02 \\
& =\frac{23.48}{23.02} \\
& =1.02
\end{align}\]
\[\begin{align}
& r=\frac{23.95}{23.48} \\
& =1.02 \\
& =\frac{24.43}{23.95} \\
& =1.02
\end{align}\]
\[\begin{align}
& r=\frac{24.92}{24.43} \\
& =1.02 \\
& =\frac{25.15}{24.92} \\
& =1.02
\end{align}\]
We see that the common ratio is constant so population growth is geometric with common ratio \[1.02\]
(b)
As shown in part (a), population growth is geometric with,\[a=20.85,r=1.02\]
By the formula of the \[{{n}^{th}}\] term of G.P.
\[\begin{align}
& {{a}_{n}}=a{{r}^{n-1}} \\
& {{a}_{n}}=20.85{{\left( 1.02 \right)}^{n-1}}
\end{align}\]
(c)
The population in 2020 can be obtained by using \[n=21\] in the general expression of population. Because the population in 2020 will be \[{{21}^{st}}\] term of the geometric sequence modelling the population.
\[\begin{align}
& {{a}_{21}}=a{{r}^{20}} \\
& =20.85{{\left( 1.02 \right)}^{20}} \\
& {{a}_{21}}=30.98 \\
& =31
\end{align}\]
In 2020, the population of Texas will be \[31\text{ million}\].