Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.7 Arithmetic and Geometric Sequences - Exercise Set 5.7 - Page 331: 131

Answer

The salary for the 7th year is\[\$3,795,957\].

Work Step by Step

: In the first year the salary of the player is \[\$3,000,000\]andan annual year the increment is 4%. So, 4% of 3000000=4/100* 3000000 =4times 30000 =120000 So, the salary of the player at the starting of the second year is: \[\$3,000,000+120,000=3,120,000\] At the starting of the third year, the salary of the player will be the salary in the seconds year increased by 4%. 4% of 3120000=4/100* 3120000 =4*31200 =124800 The salary for the third year is: \[\$3,120,000+\$124,800=\$3,244,800\] Now the series is 3000000, 3120000, 3244800……. It is a form of G.P. The nth term is found in G.P with the help of the following formula \[{{a}_{n}}=a{{r}^{\left( n-1 \right)}}\] The salary of the player accumulates according to G.P. with \[a=3000000,\,r=1\cdot 04\] and it is required to find \[{{7}^{th}}\]term. \[\begin{align} & {{a}_{n}}=a{{r}^{n-1}} \\ & {{a}_{7}}=3000000\times {{\left( 1.04 \right)}^{\left( 7-1 \right)}} \\ & =3000000\times {{\left( 1.04 \right)}^{6}} \\ & {{a}_{7}}=3795957.06 \end{align}\] Hence, salary of the player in year 7 rounded to the nearest dollar is\[\$3,795,957\].
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