Answer
$990$
Work Step by Step
We know that if we want to select $r$ objects out of $n$ regarding the order, we can do this in $_nP_r=\frac{n!}{(n-r)!}$ ways.
Hence here the number of possibilities is $_{11}P_3=\frac{11!}{(11-3)!}=990$
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 11 - Counting Methods and Probability Theory - Chapter 11 Test - Page 762: 4
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