Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter 11 Test - Page 762: 18

Answer

$\frac{1}{19}$

Work Step by Step

In this case the events are not independent, the first one has probability $\frac{5}{20}$, the second one has probability $\frac{4}{19}$, thus the probability is: $\frac{5}{20}\frac{4}{19}=\frac{1}{19}$
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