Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter 11 Test - Page 762: 20

Answer

$\frac{3}{4}$

Work Step by Step

The odds against $E$: $\frac{P(\text{not E})}{P(E)}$ The total number of outcomes in this sample: $35$, the number of outcomes satisfying the requirements in this sample: $15$, thus the odds against: $\frac{35-20}{20}=\frac{3}{4}$
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