Basic College Mathematics (10th Edition)

by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.

Published by Pearson

ISBN 10: 0134467795

ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.9 Similar Triangles - 8.9 Exercises - Page 600: 18

Answer

$P1 = 29.8yd$ $P2 = 44.7yd$

Work Step by Step

$\frac{x}{17.4} = \frac{8}{11.6}$ $x = \frac{17.4*8}{11.6} = 12yd$ $\frac{y}{11.6} = \frac{15.3}{17.4}$ $y = \frac{11.6*15.3}{17.4} = 10.2yd$ Then $P1 = 8 + 11.6 + 10.2 = 29.8yd$ $P2 = 17.4 + 15.3 + 12 = 44.7yd$

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