Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 592: 31

Hypotenuse of the triangle is $ \approx 2.8$ m

Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $(2.5)^{2} + (1.3)^{2} = H^{2}$ $6.25 + 1.69 = H^{2}$ $7.94 = H^{2}$ $H = \sqrt 7.94$ $H = 2.817...$ $H \approx 2.8$ m