Answer
Hypotenuse $\approx 12.1$ cm.
Work Step by Step
Let $H =$ hypotenuse of the triangle
$a^{2} + b^{2} = c^{2}$
$5^{2} + 11^{2} = H^{2}$
$25 + 121 = H^{2}$
$146 = H^{2}$
$H = \sqrt 146$
$H = 12.083...$
$H \approx 12.1$ cm
Basic College Mathematics (10th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0134467795
ISBN 13:
978-0-13446-779-5
Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 592: 26
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