Answer
Hypotenuse $\approx 11.7$ yd.
Work Step by Step
Let $H =$ hypotenuse of the triangle
$a^{2} + b^{2} = c^{2}$
$4^{2} + 11^{2} = H^{2}$
$16 + 121 = H^{2}$
$137 = H^{2}$
$H = \sqrt 137$
$H = 11.704...$
$H \approx 11.7$ yd
Basic College Mathematics (10th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0134467795
ISBN 13:
978-0-13446-779-5
Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 592: 27
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
