Answer
Divisible by 2, 3, 5, and 10
Work Step by Step
$90\div2=45$ with a remainder of 0
$90\div3=30$ with a remainder of 0
$90\div5=18$ with a remainder of 0
$90\div10=9$ with a remainder of 0
Therefore, 90 is divisible by 2, 3, 5, and 10.
Basic College Mathematics (10th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0134467795
ISBN 13:
978-0-13446-779-5
Chapter 2 - Multiplying and Dividing Fractions - 2.4 Writing a Fraction in Lowest Terms - 2.4 Exercises - Page 136: 6
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