Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 2 - Multiplying and Dividing Fractions - 2.4 Writing a Fraction in Lowest Terms - 2.4 Exercises - Page 136: 10

Answer

Divisible by 5

Work Step by Step

$175\div2=87$ with a remainder of 1 $175\div3=58$ with a remainder of 1 $175\div5=35$ with a remainder of 0 $175\div10=17$ with a remainder of 5 Therefore, 175 is divisible by 5.
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