Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - Algebra Review - Page 399: 7

Answer

$6 \sqrt {2}$

Work Step by Step

First, we write both numbers under the same radical: $\frac{\sqrt {144}}{\sqrt {2}} = \sqrt \frac{144}{2}$ Evaluate what is under the radical sign: $\sqrt {72}$ Rewrite $72$ as a product of a perfect square and another factor. We can use $36$ as the perfect square factor: $\sqrt {36 • 2}$ Take the square root of $36$ to solve: $6 \sqrt {2}$
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