Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - Algebra Review - Page 399: 3

Answer

$8$

Work Step by Step

First, we write both numbers under the same radical: $\sqrt {128} \div \sqrt {2} = \sqrt {\frac{128}{2}}$ Evaluate what is under the radical sign: $\sqrt {64}$ Take the square root of $64$ to solve: $8$
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