Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - Algebra Review - Page 399: 4

Answer

$\frac{5\sqrt {5}}{2}$

Work Step by Step

First, we write both numbers under the same radical: $\sqrt {\frac{125}{4}}$ Rewrite $125$ as a product of a perfect square and another factor. We can use $25$ as the perfect square factor: $\sqrt {\frac{25 • 5}{4}}$ Take the square root of $25$ in the numerator and the square root of $4$ in the denominator to solve: $\frac{5\sqrt {5}}{2}$
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