Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 1 - Tools of Geometry - 1-7 Midpoint and Distance in the Coordinate Plane - Practice and Problem-Solving Exercises - Page 54: 40

Answer

$d=10$ $M(1,-4)$

Work Step by Step

Use the distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ $d=\sqrt{(5-(-3))^2+(-7-(-1))^2}$ $d=\sqrt{(8)^2+(-6)^2}$ $d=\sqrt{64+36}$ $d=\sqrt{100}$ $d=10$ Use the midpoint formula to find the x-coordinate of the midpoint: $x_m=\frac{x_1+x_2}{2}=\frac{-3+5}{2}=\frac{2}{2}=1$ Use the midpoint formula to find the y-coordinate of the midpoint: $y_m=\frac{y_1+y_2}{2}=\frac{-1+(-7)}{2}=\frac{-8}{2}=-4$
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