Answer
$x=-\frac{5}{6}$ or $3$
Work Step by Step
$\frac{2x+1}{x+1} = \frac{14}{3x-1}$
$(2x+1)(3x-1) = 14(x+1)$
$6x^{2}+x-1 = 14x + 14$
$6x^{2}-13x-15 = 0$
$(6x+5)(x-3) = 0$
$6x+5=0$
$6x=-5$
$x=-\frac{5}{6}$
or
$x-3=0$
$x=3$
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