Answer
$x=-8$ or $8$
Work Step by Step
$\frac{x-2}{5} = \frac{12}{x+2}$
$(x-2)(x+2) = 12\times5$
$x^{2}-4 = 60$
$x^{2}-64 = 0$
$(x+8)(x-8) = 0$
$x=-8$ or $8$
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