Answer
$x=-7$ or $4$
Work Step by Step
$\frac{x+1}{3} = \frac{10}{x+2}$
$(x+1)(x+2) = 10\times3$
$x^{2}+3x+2 = 30$
$x^{2}+3x-28 = 0$
$(x+7)(x-4)=0$
$x=-7$ or $4$
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