Answer
$(x,y,z) = (4,-3,7)+n(4,2,-3)$
Work Step by Step
In general we can write an equation for a line in this form:
$(x,y,z) = (a,b,c)+n(a',b',c')$
where $(a,b,c)$ is a point on the line and $(a',b',c')$ is a direction vector
$(4,-3,7)$ is a point on the line
$(4,2,-3)$ is a direction vector
We can write an equation for this line:
$(x,y,z) = (4,-3,7)+n(4,2,-3)$