Answer
$d = 5.39$
Work Step by Step
$P_1 = (1,0,2)$
$P_2 = (3,4,-1)$
We can find the distance between these two points:
$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
$d = \sqrt{(3-1)^2+(4-0)^2+(-1-2)^2}$
$d = \sqrt{(2)^2+(4)^2+(-3)^2}$
$d = \sqrt{4+16+9}$
$d = \sqrt{29}$
$d = 5.39$
