Answer
$4x^2-49y^2 = (2x+7y)~(2x-7y)$
Work Step by Step
The general form of factoring the difference of two squares is as follows:
$x^2-y^2 = (x+y)~(x-y)$
We can factor the difference of the two squares:
$4x^2-49y^2 = (2x+7y)~(2x-7y)$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 7
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