Answer
$x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$
Work Step by Step
The general form of factoring the difference of two squares is as follows:
$x^2-y^2 = (x+y)~(x-y)$
Let's consider the given equation:
$16x^2-9 = 0$
$(4x+3)~(4x-3) = 0$
$4x+3 = 0~~$ or $~~4x-3 = 0$
$x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$
