Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 3

Answer

$2bx^2+4b^2x = (2bx)~(x+2b)$

Work Step by Step

The GCF of $~[2bx^2+4b^2x]~$ is $~2bx$ We can factor by using the GCF: $2bx^2+4b^2x = (2bx)~(x+2b)$
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