Answer
$1$
Work Step by Step
The sum of a geometric series can be found as:
$S=\dfrac{a}{1-r}$
The given series has first term, $a=\dfrac{3}{2}$ and common ratio $r =\dfrac{-1}{2}$
Hence, $S=\dfrac{\dfrac{3}{2}}{1-(\dfrac{-1}{2})}=1$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.2 - Infinite Series - Exercises - Page 498: 51
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