Answer
$2+\sqrt 2$
Work Step by Step
The sum of a geometric series can be found as:
$S=\dfrac{a}{1-r}$
Here, $a=1, r=\dfrac{1}{\sqrt 2} \lt 1$
Thus,
$S=\dfrac{a}{1-r}=\dfrac{1}{1-\dfrac{1}{\sqrt 2}}=\dfrac{\sqrt 2}{\sqrt 2-1}=2+\sqrt 2$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.2 - Infinite Series - Exercises - Page 498: 49
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
