Answer
Center: $(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius: $\sqrt 2$
Work Step by Step
We know that the standard equation of a sphere is written as:
$(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=r^2$ ...(1)
Here, $(x_0,y_0,z_0)$ represents the center and $r$ is the radius of the sphere.
Since, we have $(x - \sqrt 2)^2+(y -\sqrt 2)^2+(z + \sqrt 2)^2=2$
or, $(x - \sqrt 2)^2+(y -\sqrt 2)^2+(z - (-\sqrt 2))^2=(\sqrt 2)^2$
Compare the above equation with equation (1):
Center: $(\sqrt 2, \sqrt 2. -\sqrt 2)$ and radius: $\sqrt 2$
