University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.1 - Three-Dimensional Coordinate Systems - Exercises - Page 600: 26

Answer

$x=3,y=-1,z=2$

Work Step by Step

Definition: Consider the point $(x_0,y_0,z_0)$ on the plane. The plane is passing through the point $(x_0,y_0,z_0)$ and is perpendicular to the x-axis, y-axis, and z-axis, so $x=x_0,y=y_0$ and $z=z_0$ Thus, we have $x=3,y=-1,z=2$
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