Answer
Center :$(-2,0,2)$ and radius: $2 \sqrt 2$
Work Step by Step
We know that the standard equation of a sphere is written as:
$(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=r^2$ ...(1)
Here, $(x_0,y_0,z_0)$ represents the center and $r$ is the radius of the sphere.
Since, we have $(x+2)^2+y^2+(z-2)^2=8$
or, $(x-(-2))^2+(y-0)^2+(z-2)^2=(\sqrt 8)^2$
or, $(x-(-2))^2+(y-0)^2+(z-2)^2=( 2 \sqrt 2)^2$
Compare the above equation with equation (1):
Center :$(-2,0,2)$ and radius: $2 \sqrt 2$
