Answer
$r=\dfrac{30}{1-5\sin \theta}$
Work Step by Step
The polar equation of a conic with eccentricity $e$ and directrix $y=-k$ is defined as:
$r=\dfrac{ke}{1-e \sin \theta}$ ...(1)
We are given that the vertices are: $e=5,k=6$
Then $y=-6$
Thus, equation (1), becomes
$r=\dfrac{30}{1-5\sin \theta}$
