Answer
$2 \sqrt 3$
Work Step by Step
The area of each cross-section triangle is given as: $A=\pi r^2 =\dfrac{(2 \sqrt 4)^2 \sin 60^{\circ}}{2}=4 \sqrt 3 x$
We integrate the integral to calculate the volume as follows:
$V= \int_{0}^{1} 4 \sqrt 3 x dx$
or, $=[2 \sqrt 3 x^2]_0^1$
or, $=2 \sqrt 3$
