Answer
See explanations.
Work Step by Step
Step 1. As the velocity is inversely proportional to $\sqrt s$, we have $v(s)=\frac{k}{\sqrt s}$, where $k$ is a constant.
Step 2. Evaluate the acceleration: $a=\frac{dv}{dt}=\frac{dv}{ds}\frac{ds}{dt}=-\frac{k}{2s\sqrt s}v=-\frac{k}{2s\sqrt s}(\frac{k}{\sqrt s})=-\frac{k^2}{2s^2}$
This is inversely proportional to $s^2$
