Answer
See explanations.
Work Step by Step
Step 1. Given the velocity $v(s)=k\sqrt s$, assume $s=s(t)$; we can calculate the accelerations as:
$a=\frac{dv}{dt}=\frac{dv}{ds}\frac{ds}{dt}$.
Step 2. Using the relation that $\frac{ds}{dt}=v=k\sqrt s$, we have:
$a=\frac{k}{2\sqrt s}(k\sqrt s)=\frac{k^2}{2}$, which is a constant.
